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Question

Solve each equation for x, where x in [0, 2pi].

a) sec x csc x - 2 csc x = 0

b) 3 sec ^2 x - 4 = 0

c) 2 sin x sec x - 2 square root of 3 sin x = 0

d) 2 cot x + sec^2 x = 0

e) cot x csc^2 x = 2 cot x

f) 3 tan^3 x - tan x = 0

Solution

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(a) We would like to solve the equation secxcscx2cscx=0\color{#4257b2}\sec x\csc x-2\csc x=0 for 0x2π\color{#4257b2}0 \leq x \leq 2\pi. First, we note that all terms contain cscx\color{#4257b2}\csc x, so we can take it as a common factor.

secxcscx2cscx=0\sec x\csc x-2\csc x=0

cscx(secx2)=0\csc x\left(\sec x-2\right)=0

Now we can use the zero-factor property to find the values of x\color{#4257b2}x.

cscx=0   or   secx2=0\csc x=0\ \ \ \text{or}\ \ \ \sec x-2=0

cscx=0   or   secx=2\csc x=0\ \ \ \text{or}\ \ \ \sec x=2

But we know that cscx1\color{#4257b2}|\csc x| \geq 1, so the solution cscx=0\color{#4257b2}\csc x=0 is refused.

secx=2\sec x=2

But we know that secx=1cosx\color{#4257b2}\sec x=\dfrac{1}{\cos x}, so we can use this identity in our equation.

1cosx=2\dfrac{1}{\cos x}=2

cosx=12\cos x=\dfrac{1}{2}

cos1(cosx)=cos1(12)\cos^{-1}\left(\cos x\right)=\cos^{-1}\left(\dfrac{1}{2}\right)

x=cos1(12)x=\cos^{-1}\left(\dfrac{1}{2}\right)

x=π3x=\dfrac{\pi}{3}

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