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Question

Solve each polynomial equation.

x34x2+4x16=0x^3-4 x^2+4 x-16=0

Solution

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Answered 1 year ago
Answered 1 year ago
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Given polynomial is

x34x2+4x16=0x^3-4x^2+4x-16=0

We can solve for xx by grouping and finding common factors between terms:

(x34x2)+(4x16)=0x2(x4)+4(x4)=0(x2+4)(x4)=0\begin{aligned} (x^3-4x^2)+(4x-16)&=0\\ x^2(x-4)+4(x-4)&=0\\ (x^2+4)(x-4)&=0 \end{aligned}

Now, using the zero-product property, we get:

x2+4=0x4=0x2=4x=4x=±2ix=4\begin{aligned} x^2+4=0\quad&\lor\quad x-4=0\\ x^2=-4\quad&\lor\quad x=4\\ x=\pm 2i\quad&\lor\quad \boxed{x=4} \end{aligned}

Since we only want the real solutions, it follows that x=4x=4 is the only solution.

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