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Question

Solve the equation of quadratic form. x410x2+25=0x^{4}-10 x^{2}+25=0

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x410x2+25=0Write the equation in quadratic form(x2)210(x2)+25=0Let u=x2, so(x2)210(x2)+25=0u210u+25=0Factor the trinomial(u5)2=0Set the factor equal to 0u5=0u=5Back - substitute u=x2 and solve for xx2=5Therefore,x2=±5x=±5\begin{gathered} {x^4} - 10{x^2} + 25 = 0 \\ \textcolor{#4257b2}{ {\text{Write the equation in quadratic form}}} \\ {\left( {{x^2}} \right)^2} - 10\left( {{x^2}} \right) + 25 = 0 \\ \textcolor{#4257b2}{ {\text{Let }}u = {x^2},{\text{ so}}} \\ \underbrace {{{\left( {{x^2}} \right)}^2} - 10\left( {{x^2}} \right) + 25 = 0}_ \Downarrow \\ {u^2} - 10u + 25 = 0 \\ \textcolor{#4257b2}{{\text{Factor the trinomial}}} \\ {\left( {u - 5} \right)^2} = 0 \\ \textcolor{#4257b2}{ {\text{Set the factor equal to 0}}} \\ u - 5 = 0 \Rightarrow u = 5 \\ \textcolor{#4257b2}{ {\text{Back - substitute }}u = {x^2}{\text{ and solve for }}x} \\ {x^2} = 5 \\ \textcolor{#4257b2}{{\text{Therefore}}{\text{,}}} \\ \sqrt {{x^2}} = \pm \sqrt 5 \\ x = \pm \sqrt 5 \\ \end{gathered}

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