Question

Solve the following differential equations:

$y^{\prime}=(y-3)^2 \ln t$

Solution

VerifiedAnswered 2 years ago

Answered 2 years ago

Step 1

1 of 8We have to solve the given differential equation

$\begin{aligned} y'=(y-3)^2\ln{t}. \end{aligned}$

Then we have the equation of the form

$\begin{aligned} y'=p(t)q(y), \end{aligned}$

where $p(t)=\ln{t}$ and $q(y)=(y-3)^2$.

## Create a free account to view solutions

By signing up, you accept Quizlet's Terms of Service and Privacy Policy

## Create a free account to view solutions

By signing up, you accept Quizlet's Terms of Service and Privacy Policy

## Recommended textbook solutions

#### Thomas' Calculus

14th Edition•ISBN: 9780134438986 (11 more)Christopher E Heil, Joel R. Hass, Maurice D. Weir10,142 solutions

#### Calculus and Its Applications

13th Edition•ISBN: 9780321848901 (7 more)David C. Lay, David I. Schneider, Larry J. Goldstein, Nakhlé H. Asmar3,865 solutions

#### Calculus: Early Transcendentals

8th Edition•ISBN: 9781285741550 (5 more)James Stewart11,084 solutions

#### Calculus: Early Transcendentals

9th Edition•ISBN: 9781337613927Daniel K. Clegg, James Stewart, Saleem Watson11,050 solutions

## More related questions

- differential equations

1/4

- differential equations

1/7