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Question

Solve the following equation.

2tt+1+4t1=2\frac{2 t}{t+1}+\frac{4}{t-1}=2

Solution

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Pythagoras theorem:Squareofthehypotenuseisequaltosumofthesquaresofothertwosidesinarighttriangle{\color{#c34632}\textbf{Pythagoras theorem:} Square of the hypotenuse is equal to sum of the squares of other two sides in a right triangle}

Let us call the unknown side as xx

Using the Pythagoras theorem, we can write

x2=52+52x^2=5^2+5^2

x2=252x^2=2\cdot 5^2

Take the square root of both sides

x=252x=\sqrt{2\cdot 5^2}

x=252x=\sqrt{2}\cdot \sqrt{5^2}

x=527.07x=5\sqrt{2}\approx7.07

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