## Related questions with answers

Solve the given problem.

A frog leaps from a stump three feet high and lands four feet from the base of the stump. We can consider the initial position of the frog to be at $(0,3)$ and its landing position to be at $(4,0)$.

It is determined that the height $h$ in feet of the frog as a function of its distance $x$ from the base of the stump is given by

$h(x)=-0.5 x^2+1.25 x+3 .$

(a) How high was the frog when its horizontal distance $x$ from the base of the stump was $2$ feet?

(b) What was the horizontal distance from the base of the stump when the frog was $3.25$ feet above the ground?

(c) At what horizontal distance from the base of the stump did the frog reach its highest point?

(d) What was the maximum height reached by the frog?

Solution

VerifiedGiven:

$h(x)=-0.5x^2+1.25x+3$

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