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Question

Solve the given problems.

The vertical cross-section of a culvert under a road is elliptical. The culvert is 1818 m wide and 1212 m high. Find an equation to represent the perimeter of the culvert with the origin at road level and 2.02.0 m above the top of the culvert.

Solution

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Answered 2 years ago
Answered 2 years ago
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The center of the ellipse is at (0,8)(0,-8). Using the given dimensions for the ellipse, we can find the values of aa and bb.

(xh)2a2+(yk)2b2=12a=18a=92b=12b=6\begin{align*} \dfrac{\left(x-h\right)^2}{a^2}+\dfrac{\left(y-k\right)^2}{b^2}&=1\\ 2a&=18\longrightarrow a=9\\ 2b&=12\longrightarrow b=6 \end{align*}

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