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Question

Solve the IVP. Check that your answer satisfies the ODE as well as the initial conditions. Show the details of your work. y''+y'-6y=0, y(0)=10, y'(0)=0

Solution

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We have

y+y6y=0y''+y'-6y=0

The characteristic equation,

λ2+λ6=0its roots:λ1=2andλ2=3\begin{gather*} \lambda^{2} + \lambda - 6 = 0 \\ \text{its roots:} \quad \lambda_{1} = 2 \quad \text{and} \quad \lambda_{2} = -3 \end{gather*}

where we see that we have a case of two distinct real roots, which means that the general solution of this Second-Order Linear ODE would be of the form

y=C1eλ1x+C2eλ2x\mathbf{y=C_{1}e^{\lambda_{1} x} + C_{2}e^{\lambda_{2} x}}

Therefore,

y=C1e2x+C2e3xy=C_{1}e^{2x} + C_{2}e^{-3x}

and

y=2C1e2x3C2e3xy'=2C_{1}e^{2x} -3C_{2}e^{-3x}

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