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Question

Solve the logarithmic equation algebraically. Approximate the result to three decimal places. 7+3lnx=57+3 \ln x=5

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Answered 2 years ago
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To solve for the given logarithmic equation, we need to rewrite it in exponential form and then evaluate the following:

7+3ln(x)=57+3ln(x)7=573ln(x)=2ln(x)=23eln(x)=e(23)x=e(23)x=0.51342x0.513\begin{aligned} 7+3\ln{(x)}&=5\\ 7+3\ln{(x)}-7&=5-7\\ 3\ln{(x)}&=-2\\ \ln{(x)}&=-\frac{2}{3}\\ e^{\ln{(x)}}&=e^{(-\frac{2}{3})}\\ x&=e^{(-\frac{2}{3})}\\ x&=0.51342\\ x&\approx0.513 \end{aligned}

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