Question

Solve the Problem using elimination by addition

2mn=102 m-n=10

m2n4m-2 n--4

Solution

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Answered 1 year ago
Answered 1 year ago
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We will multiply the second equation by 22:

2(m2n)=2(4)2m4n=8\begin{align*} 2\cdot(m-2n)&=2\cdot(-4)\\ 2m-4n&=-8 \end{align*}

The given system is equivalent to the following system:

2mn=10(1)2m4n=8(2)\begin{align*} 2m-n&=10 &&(1)\\ 2m-4n&=-8 &&(2) \end{align*}

Now, let us substract the equation (2)(2) from (1)(1)

2mn(2m4n)=10(8)2mn2m+4n=10+83n=18n=6\begin{align*} 2m-n-(2m-4n)&=10-(-8)\\ \cancel{2m}-n-\cancel{2m}+4n&=10+8\\ 3n&=18\\ n&=6 \end{align*}

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