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Question

Solve the system graphically or algebraically. Explain your choice of method.

{xy1=05x2y+1=0\left\{\begin{aligned} x y-1 &=0 \\ -5 x-2 y+1 &=0 \end{aligned}\right.

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Answered 2 years ago
Answered 2 years ago
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We will start with the substitution method in order to come to quadratic equation:

xy1=0xy=1/÷y,x=1y5x2y+1=0\begin{align*} xy-1&=0\to xy=1/\div y,\boxed{x=\frac{1}{y}}\\ -5x-2y+1&=0\\ \end{align*}

51y2y+1=05y2y+1=0/y52y2+y=0\begin{align*} -5\cdot \frac{1}{y}-2y+1&=0\\ -\frac{5}{y}-2y+1&=0/\cdot y\\ -5-2y^2+y&=0 \end{align*}

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