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Question

Solve the system of linear equations using the substitution method.

x+y+z=45x+5y+5z=12x4y+z=9\left. \begin{array} { l } { x + y + z = 4 } \\ { 5 x + 5 y + 5 z = 12 } \\ { x - 4 y + z = 9 } \end{array} \right.

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We will solve the system.

To solve for the system we will use substitution.

Using equation 22, let's factor out 55 from the left side of the equation:

5(x+y+z)=125\left(x+y+z\right)=12

Since x+y+z=4x+y+z=4:

5(4)=1220=12\begin{aligned} 5\left(4\right)&=12\\ 20&=12 \end{aligned}

Since the result is a false equation, therefore, the system has no solution.

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