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Question

Square ABCD has vertices at (0, 0), (0, 2), (2, 2), and (2, 0). Perform the indicated transformation. Then give the coordinates of figure

ABCDA ^ { \prime } B ^ { \prime } C ^ { \prime } D ^ { \prime }

.

(x,y)(x+3,y)( x , y ) \rightarrow ( x + 3 , y )

Solution

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(0+3,0)=(3,0)(0+3,0) = (3,0) (0+3,2)=(3,2)(0+3,2) = (3,2) (2+3,2)=(5,2)(2+3,2) = (5,2)

(2+3,0)=(5,0)(2+3,0) = (5,0)

(x+3,y)(x+3,y) means we need to add 3 to each x-value.

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