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# Sterling silver is a solid solution of silver and copper. If a piece of a sterling silver necklace has a mass of 105.0 g and a volume of 10.12 mL, calculate the mass percent of copper in

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In this exercise, we need to calculate the mass percent of copper (Cu) in a given piece of necklace that also contains silver.

The given information is listed below.

m(sterling silver necklace) = 105.0 g V(sterling silver necklace) = 10.12 cm$^3$

Also, we are told that we can assume that the mass of the sterling silver necklace is the sum of the mass of copper and the mass of silver. And the volume of the necklace is equal to the sum of the volume of copper and the volume of silver. Hence, we can write:

m(sterling silver necklace) = m(Cu) + m(Ag) = 105.0 g V(sterling silver necklace) = V(Cu) + V(Ag) = 10.12 cm$^3$

We are not given one crucial piece of information, but we can find it in Table 1.5 in the textbook. This table contains the densities (d) of a few selected elements, among which are copper and silver.

d(Cu) = 8.96 g/cm$^3$ d(Ag) = 10.49 g/cm$^3$

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