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Question

Study of why EMS workers leave the job. A study of fulltime emergency medical service (EMS) workers published in the Journal of Allied Health (Fall 2011) found that only about 3% leave their job in order to retire. (See Exercise 3.453.45, p. 158.) Assume that the true proportion of all fulltime EMS workers who leave their job in order to retire is p=.03p=.03. In a random sample of 1,000 full-time EMS workers, let p^\hat{p} represent the proportion who leave their job in order to retire. Compute P(p^<.05)P(\hat{p}<.05). Interpret this result.

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Answered 1 year ago
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In this exercise, calculate the probability, mean, and standard deviation of p^\hat{p}'s sampling distribution.

According to the information provided, n=1,000n = 1,000 random sample is a Ems full time worker, and p=0.03p = 0.03 retire their job order.

Givens:
pp 0.03
nn 1,000

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