## Related questions with answers

**Study of why EMS workers leave the job**. A study of fulltime emergency medical service (EMS) workers published in the Journal of Allied Health (Fall 2011) found that only about 3% leave their job in order to retire. (See Exercise $3.45$, p. 158.) Assume that the true proportion of all fulltime EMS workers who leave their job in order to retire is $p=.03$. In a random sample of 1,000 full-time EMS workers, let $\hat{p}$ represent the proportion who leave their job in order to retire. Compute $P(\hat{p}<.05)$. Interpret this result.

Solution

VerifiedIn this exercise, calculate the probability, *mean*, and *standard deviation* of $\hat{p}$'s sampling distribution.

According to the information provided, $n = 1,000$ random sample is a Ems full time worker, and $p = 0.03$ retire their job order.

Givens: | |
---|---|

$p$ | 0.03 |

$n$ | 1,000 |

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