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Question

Sucrose, C12H22O11\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}, is a sugar used to sweeten many foods. Inside the body, it is broken down to produce H2O\mathrm{H}_{2} \mathrm{O} and CO2.\mathrm{CO}_{2}.

C12H22O11+12O212CO2+11H2O\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}+12 \mathrm{O}_{2} \longrightarrow 12 \mathrm{CO}_{2}+11 \mathrm{H}_{2} \mathrm{O}

List all of the mole ratios that can be determined from this equation.

Solution

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Answered 2 years ago
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The decomposition of the sucrose is

C12H22O11+12O212CO2+11H2O\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}+12 \mathrm{O}_{2} \longrightarrow 12 \mathrm{CO}_{2}+11 \mathrm{H}_{2} \mathrm{O}

The number before the molecule is the number of moles. Below, we list the number of moles for each molecule

Molecule no. of moles
C12H22O11\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11} 1
O2\mathrm{O}_{2} 12
CO2\mathrm{CO}_{2} 12
H2O\mathrm{H}_{2} \mathrm{O} 11

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