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Question

Suppose a and b are real numbers other than zero and that a>b. State whether the inequality is true or false for all real numbers a and b. 1a>1b\frac{1}{a}>\frac{1}{b}

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Let's solve given problem

1a>1b\frac{1}{a}>\frac{1}{b}

First, we will substract 1b\frac{1}{b} from both sides of inequality

1a1b>0\frac{1}{a}-\frac{1}{b}>0

LCD is abab

baab>0\frac{b-a}{ab}>0

If ba<0b-a<0 (a>b)(a>b) and ab>0ab>0 then

baab<0\frac{b-a}{ab}<0

so the given statement is not true\color{#c34632}{\text{not true}} for all real numbers aa and bb other than zero and that a>ba>b. For example, if a=1a=-1 b=2b=-2 then 11<12\color{#c34632}{\frac{1}{-1}<\frac{1}{-2}}.

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