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Suppose a piece of dust finds itself on a CD. If the spin rate of the CD is 500 rpm, and the piece of dust is 4.3 cm from the center, what is the total distance traveled by the dust in 3 minutes? (Ignore accelerations due to getting the CD rotating.)

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Knowns\textbf{Knowns}

\normalsize We know that the rotational kinematic equations that describe the relationship among the rotational angle θ\color{#c34632}\theta, the initial angular velocity ωo\color{#c34632}\omega_o, the angular acceleration α\color{#c34632}\alpha and time t\color{#c34632}t is given by:

θ=ωo t+12αt2\begin{gather*} \theta = \omega_o\ t + \dfrac{1}{2}\alpha t^2\tag{1} \end{gather*}

We also know that the relation between the linear distance x\color{#c34632}x and the rotational angle θ\color{#c34632}\theta is given by:

x=rθ\begin{gather*} x = r\theta\tag{2} \end{gather*}

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