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Question

Suppose angles A and B are a linear pair. Given the relationships below, find the measure of angles A and B. Round your answers to the nearest tenth of a degree. mA=3x+7;mB=5x+20m \angle A=3 x+7^{\circ} ; m \angle B=5 x+20^{\circ}

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A linear pair consists of adjacent angles that form a straight angle so they are supplementary. Hence, we can write:

mA+mB=180°m\angle A+m\angle B=180\text{\textdegree}

(3x+7°)+(5x+20°)=180°(3x+7\text{\textdegree})+ (5x+20\text{\textdegree})=180\text{\textdegree}

8x+27°=180°8x+27\text{\textdegree}=180\text{\textdegree}

8x=153°8x =153\text{\textdegree}

x=153°8x =\dfrac{153\text{\textdegree}}{8}

x=19.125°x =19.125\text{\textdegree}

So, the measures of the angles are:

mA=3(19.125°)+7°64.4°mB=5(19.125°)+20°115.6°\begin{align*} m\angle A&=3(19.125\text{\textdegree})+7\text{\textdegree} \approx \color{#c34632}64.4\text{\textdegree}\\ m\angle B&=5(19.125\text{\textdegree})+20\text{\textdegree} \approx \color{#c34632}115.6\text{\textdegree} \end{align*}

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