## Related questions with answers

Suppose that a couple will have three children. Letting $B$ denote a boy and $G$ denote a girl:

Assuming that all sample space outcomes are equally likely, find the probability of each of the events given in part $b$.

Solutions

VerifiedAssuming that all sample space outcomes are equally likely, we will determine the probability of each of the events by using the following equation :

$\begin{align*} P(b_i)= \dfrac{\text{the number of sample space outcomes that correspond to the event}} {\text{the total number of sample space outcomes}} \end{align*}$

From the previous tasks, we have determined that the total number of sample space outcomes is $8$.

The probability of the first event from part b is :

$\begin{align*} P(b_1)= \dfrac{2} {8} = \dfrac{1} {4} \end{align*}$

Moreover, the probability of the second event from part b is :

$\begin{align*} P(b_2)= \dfrac{3} {8} \end{align*}$

To be able to find the probability of each of the events given in part *b*, we count the number of outcomes in each event, then divide it by the total number of outcomes in the sample space which is $8$.

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