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Question

Suppose that the population dynamics of a species obeys a modified version of the logistic differential equation having the following form: dNdt=r(1NK)2N\frac{d N}{d t}=r\left(1-\frac{N}{K}\right)^{2} N where r0 and K>0r \neq 0 \text { and } K>0 Apply the local stability criterion to the equilibrium N^=K.\hat{N}=K. What do you think your answer means about the stability of this equilibrium?

Solution

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The derivative of the differential equation with respect to NN is

g(N)=2r(1NK)(2NK+1)g'(N)=2r \left( 1 - \frac { N } { K } \right) \left(-\frac{2N}{K}+1 \right)

Now, g(K)=2r(1KK)(2KK+1)=0g'(K)=2r \left( 1 - \dfrac { K } { K } \right) \left(-\dfrac{2K}{K}+1 \right)=0.

N^\hat{N} is locally stable if g(N^)<0g'(\hat{N})<0 , and N^\hat{N} is unstable if g(y^)>0g'(\hat{y})>0. Here g(K)=0g'(K)=0 which means that it cannot be said whether N^=K\hat{N}=K is locally stable equilibrium or not.

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