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Question

Suppose that two tanks, 1 and 2, each with a large opening at the top, contain different liquids. A small hole is made in the side of each tank at the same depth hh below the liquid surface, but the hole in tank 1 has half the cross-sectional area of the hole in tank 2. What is the ratio ρ1/\rho_1 / ρ2\rho_2 of the densities of the liquids if the mass flow rate is the same for the two holes?

Solution

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Answered 8 months ago
Answered 8 months ago
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Given:

  • The depth of the hole hh
  • The mass flow rate is equal for both fluids.
  • The ratio of the cross-sectional areas: A1=1/2A2A_1 = 1/2 A_2

Required:

  • In this problem, we are asked to find the ratio of the densities ρ1/ρ2\rho_1/ \rho_2

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