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Suppose that x=f(t)x=f(t) and y=g(t)y=g(t) satisfy the relation. Relate dx/dtd x / d t and dy/dtd y / d t. tan1(xy)=π/4\tan ^{-1}(x-y)=\pi / 4

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Answered 2 years ago
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Let tan1(xy)=π4\tan^{-1}(x-y)=\dfrac{\pi}{4}, where xx and yy are functions of tt. To apply formula (2) we set F(x,y)=tan1(xy)π4F(x,y)=\tan^{-1}(x-y)-\dfrac{\pi}{4}. Then:

Fx(x,y)=1(xy)2+1Fy(x,y)=1(xy)2+1\begin{aligned} F_x(x,y)&=\dfrac{1}{(x-y)^2+1}\\ F_y(x,y)&=-\dfrac{1}{(x-y)^2+1} \end{aligned}

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