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Question

Suppose the circuit described by the equation below

dIdt+RLI=1LV(t)\frac{dI}{dt}+\frac{R}{L}I= \frac{1}{L}V(t)

is driven by a sinusoidal voltage source V(t)=VsinωtV(t)=V \sin \omega t (where VV and ω\omega are constant).

(a) Show that

I(t)=VR2+L2ω2(RsinωtLωcosωt)+Ce(R/L)tI(t)=\frac{V}{R^2+L^2 \omega^2}(R \sin \omega t-L \omega \cos \omega t)+C e^{-(R / L) t}

(b) Let Z=R2+L2ω2Z=\sqrt{R^2+L^2 \omega^2}. Choose θ\theta so that Zcosθ=RZ \cos \theta=R and Zsinθ=Z \sin \theta= LωL \omega. Use the addition formula for the sine function to show that

I(t)=VZsin(ωtθ)+Ce(R/L)tI(t)=\frac{V}{Z} \sin (\omega t-\theta)+C e^{-(R / L) t}

This shows that the current in the circuit varies sinusoidally apart from a DC term (called the transient current in electronics) that decreases exponentially.

Solution

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We are given:

V(t)=VsinωtV(t)=V\sin \omega t

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