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Surface Integrals SG(r)dA\iint_S G(\mathbf{r}) d A. Using SG(r)dA=RG(r(u,v))N(u,v)dudv\iint_S G(\mathbf{r}) d A=\iint_R G(\mathbf{r}(u, v))|\mathbf{N}(u, v)| d u d v or SG(r)dA=RG(x,y,f(x,y))1+(fx)2+(fy)2dxdy\iint_S G(\mathbf{r}) d A=\iint_{R^*} G(x, y, f(x, y)) \sqrt{1+\left(\frac{\partial f}{\partial x}\right)^2+\left(\frac{\partial f}{\partial y}\right)^2} d x d y, evaluate thise integral for the given data. (Show the details.)

G=z,S:x2+y2+z2=9,z0G=z, \quad S: x^2+y^2+z^2=9, \quad z \geqq 0

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Answered 2 years ago
Answered 2 years ago
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We know that

SG(r)dA=RG(x,y,f(x,y))1+(fx)2+(fy)2(1)\int\int_S G(\mathbf{r}) dA=\int\int_{R^*} G(x,y,f(x,y))\sqrt{1+\left(\frac{\partial f}{\partial x}\right)^2+\left(\frac{\partial f}{\partial y}\right)^2} \tag{1}

where SS is the surface given by z=f(x,y)z=f(x,y) and RR^* is the projection of SS into the xyxy plane.

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