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Symmetry: For y=f(t,y)y^{\prime}=f(t,y) do the following: (a)(a) Sketch the direction fields and identify visual symmetries. (b)(b)Conjecture how these graphical symmetries relate to algebraic symmetries in f(t,y)f(t,y).y=y2ty^{\prime}=\frac{y^{2}}{t}

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The differential equation

y=y2ty^{'}=\dfrac{y^{2}}{t}

Here we can see the slope yy^{'} depends on both the coordinates of axis and for fixed tt the value of slope for ±y\pm y is same but there is no symmetric about horizontal axis but sign of tt define sign of slope which reflect visual symmetric in directional field across vertical axis. Here you can clearly see from graph there is no solution symmetricity

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