## Related questions with answers

Question

Take the derivative of the previous expression to find an expression for sinh(2x).

Solution

VerifiedStep 1

1 of 3$\begin{align*} \left[\cosh(x)\right]'&=\sinh(x) \\ \left[\sinh(x)\right]'&=\cosh(x) \\ \end{align*}$

It's important to remark that we will need to use the derivatives of $\cosh(x)$ and $\sinh(x)$ in order to find the expression for $\sinh(2x)$.

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