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Question

Take the derivative of the previous expression to find an expression for sinh(2x).

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[cosh(x)]=sinh(x)[sinh(x)]=cosh(x)\begin{align*} \left[\cosh(x)\right]'&=\sinh(x) \\ \left[\sinh(x)\right]'&=\cosh(x) \\ \end{align*}

It's important to remark that we will need to use the derivatives of cosh(x)\cosh(x) and sinh(x)\sinh(x) in order to find the expression for sinh(2x)\sinh(2x).

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