Question

The ages (in weeks) at which 6 infants learned to crawl are $23, 37, 33, 39, 29$, and $31$. What is the mean absolute deviation for the age at which the infants learned to crawl, to the nearest tenth?

Solution

VerifiedFind the mean:

$\dfrac{23+37+33+39+29+31}{6}=\dfrac{192}{6}=32$

$$$$

Subtract the mean from each data value. Then find the absolute value of the difference:

$x_i$ | abs$(x_i-\overline{x})$ |
---|---|

23 | 9 |

37 | 5 |

33 | 1 |

39 | 7 |

29 | 3 |

31 | 1 |

Find the mean of the absolute values of the differences.\

$MAD=\dfrac{9+5+1+7+3+1}{6}=\dfrac{26}{6}\approx\color{#c34632}4.3$

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