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Question

# In 1902, 44 loaves of bread cost the same amount as 1 loaf of bread in 2006. If a loaf of bread in 2006 costs \$1.72 more than in 1902, find the cost of a loaf of bread in 1902.

Solutions

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Step 1
1 of 2

Let $x$ be the cost of a loaf of bread in 1902 and $y$ be the cost of a loaf of bread in 2006.

In 1902, 44 loaves of bread cost the same amount as 1 loaf of bread in 2006 so:

$44x=y\tag{1}$

A loaf of bread in 2006 costs $\1.72$ more than in 1902:

$y=x+1.72\tag{2}$

Substitute (1) to (2) and solve for $x$:

$44x=x+1.72$

$43x= 1.72$

$x=0.04$

So, the cost of a loaf of bread in 1902 was:

$\color{#c34632}\0.04$

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