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Question

Test for symmetry with respect to each axis and to the origin. y=x3+xy=\left|x^{3}+x\right|

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Answered 9 months ago
Answered 9 months ago
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We have y=x3+xy= \left| x^3+x\right|

First: we’ll test the equation for symmetry with respect to the x-axis\color{#4257b2}\text{First: we'll test the equation for symmetry with respect to the x-axis}:

(y)=x3+x(-y)= \left| x^3+x\right|( Replace y by -y)

y=x3+x\Rightarrow y=- \left| x^3+x\right|

The result is not an equivalent equation.

Therefore the graph is not symmetric with respect to the x-axis

Second: we’ll test the equation for symmetry with respect to the y-axis\color{#4257b2}\text{Second: we'll test the equation for symmetry with respect to the y-axis}:

y=(x)3xy= \left| (-x)^3-x\right|( Replace x by -x)

y=(x3+x)=x3+x\Rightarrow y= \left| -(x^3+x)\right| = \left| x^3+x\right|

The result is an equivalent equation.

Therefore the graph is symmetric with respect to the y-axis

Third: we’ll test the equation for symmetry with respect to the origin\color{#4257b2}\text{Third: we'll test the equation for symmetry with respect to the origin}:

y=(x)3x-y= \left|(- x)^3-x\right|( Replace y by -y and x by -x)

y=x3+x\Rightarrow -y= \left| x^3+x\right|

The result is not an equivalent equation.

Therefore the graph is not symmetric with respect to the origin

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