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Test the given claim. Identify the null hypothesis, alternative hypothesis, test statistic, P-value or critical value(s), conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method unless your instructor specifies otherwise.

A simple random sample of 50 adults is obtained, and each person's red blood cell count (in cells per microliter) is measured. The sample mean is 5.235.23. The population standard deviation for red blood cell counts is 0.540.54. Use a 0.010.01 significance level to test the claim that the sample is from a population with a mean less than 5.45.4, which is a value often used for the upper limit of the range of normal values. What do the results suggest about the sample group?

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P-VALUE METHOD

H0:μ=54H_0:\mu=54

H1:μ<54H_1:\mu<54

The value of the test statistic is then:

z=xμσ/n=5.235.45.4/500.22z=\dfrac{\overline{x}-\mu}{\sigma/\sqrt{n}}=\dfrac{5.23-5.4}{5.4/\sqrt{50}}\approx -0.22

The corresponding P-value (probability) can then be found using table A-2:

P=P(Z<0.22)=0.4129P=P(Z<-0.22)=0.4129

If the P-value is smaller than the significance level, reject the null hypothesis:

P>0.01 Fail to reject H0P>0.01\Rightarrow \text{ Fail to reject } H_0

There is no significant evidence to support the claim.

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