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Question

The 1360kg1360-\mathrm{kg} car travels along a straight road of increasing grade whose vertical profile is given by the equation shown. The magnitude of the car's velocity is a constant 100 km/h100 \mathrm{~km} / \mathrm{h}. When x=200 mx=200 \mathrm{~m}, what are the xx and yy components of the total force acting on the car (including its weight)?

Strategy: You know that the tangential component of the car's acceleration is zero. You can use this condition together with the equation for the profile of the road to determine the xx and yy components of the car's acceleration.

Solution

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Answered 1 year ago
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Given:

  • Mass of the car: m=1360 kgm = 1360 \text{ kg}
  • Magnitude of the car's velocity: v=100kmhrv= 100 \frac{\text{km}}{\text{hr}}
  • Desired xx-position: x=200 mx = 200 \text{ m}

Required:

  • x-component of the total force: Fx\sum{F_x}
  • y-component of the total force: Fy\sum{F_y}

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