## Related questions with answers

Question

The angular position of a point on the rim of a rotating wheel is given by $\theta = 4.0t - 3.0t^2 + t^3$, where $\theta$ is in radians and t is in seconds. What is the instantaneous angular acceleration at the end of this time interval?

Solution

VerifiedAnswered 1 year ago

Answered 1 year ago

Step 1

1 of 4**Givens**:

The angular position, $\theta=4t-3t^2+t^3$ where $t$ is time in seconds, and $\theta$ is the angle in radians.

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