Question

The annihilation of an electron and a positron, each with negligible kinetic energy, results in the production of two photons with the same energy. Determine the wavelength of each photon.

Solution

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Answered 2 years ago
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The wavelength of that photon is:

λ=hcEγ=(6.6261034Js)(3108ms)8.21014J=2.42pm\begin{align*} \lambda&=\frac{hc}{E_{\gamma}}\\ &=\frac{(6.626\cdot 10^{-34}\,\text{Js})(3\cdot 10^{8}\frac{\,\text{m}}{\,\text{s}})}{8.2\cdot 10^{-14}\,\text{J}}\\ &=\boxed{2.42\,\text{pm}} \end{align*}

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