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Question

The area A of a circle in terms of the circle's radius r is A= πr². a. Explain the restrictions on the domain of the function A = πr² and the inverse function in this context. b. Write the inverse function of A = πr². c. Use the inverse function you wrote in part (b) to find the radius of a circle that has an area of 50.25 in.². Round your answer to the nearest inch.

Solution

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(a)\textbf{(a)}

A negative radius does not make sense so we restrict the radius to:

r0\color{#c34632}{r\geq 0}

(b)\textbf{(b)}

To find the inverse of AA, we simply solve for rr in terms of AA. Dividing both sides by π\pi, we have:

Api=r2\dfrac{A}{pi}=r^2

Take the positive square root of both sides:

Aπ=r\sqrt{\dfrac{A}{\pi}}=r

r=Aπ\color{#c34632}{r=\sqrt{\dfrac{A}{\pi}}}

(c)\textbf{(c)}

Using the inverse function from part (b), substitute A=50.25A=50.25 and solve for rr:

r=50.25πr=\sqrt{\dfrac{50.25}{\pi}}

r4 in.\color{#c34632}{r\approx 4\text{ in.}}

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