Question

The Bernoulli equation is valid for steady, inviscid, incompressible flows with constant acceleration of gravity. Consider flow on a planet where the acceleration of gravity varies with height so that g=g0czg=g_{0}-c z, where g0g_{0} and c are constants. Integrate “F = ma” along a streamline to obtain the equivalent of the Bernoulli equation for this flow.

Solution

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Answered 2 years ago
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According to second law of Newton

Fs=mas\sum F_{s} =\sum ma_{s}

Applying Bernoulli's equation

dP+12ρdV2+γdZ=0Replaceγ=ρgg=g0czdP+d(12ρV2)+ρ(g0cz)dz=0integrating equation12dp+12d(12ρV2)+ρ12(g0cz)dz=0[p]12+12ρ[v]12+ρg0[z]12ρc[z22]12=0p2p1+12ρ[v22v12]+ρg0[z2z1]12ρc[z22z12]=0p+12ρV2+ρg0z12ρcz2=k\begin{align*} dP+\dfrac{1}{2}\rho dV^{2}+\gamma dZ &= 0\\ & \text{Replace}\\ \gamma&= \rho g\\ g &=g_{0}-cz\\ dP+ d(\dfrac{1}{2}\rho V^{2})+\rho(g_{0}-cz)dz &=0\\ & \text{integrating equation}\\ \int _{1}^{2}dp+\int _{1}^{2}d(\dfrac{1}{2}\rho V^{2})+\rho \int _{1}^{2}(g_{0}-cz)dz &=0\\ [p]_{1}^{2}+\dfrac{1}{2}\rho[v]_{1}^{2}+\rho g_{0}[z]_{1}^{2}- \rho c[\dfrac{z^{2}}{2}]_{1}^{2}& =0\\ p_{2}-p_{1} +\dfrac{1}{2}\rho[v_{2}^{2}-v_{1}^{2}]+\rho g_{0}[z_{2}-z_{1}] -\dfrac{1}{2}\rho c[z_{2}^{2}-z_{1}^{2}] &=0\\ p+\dfrac{1}{2}\rho V^{2} +\rho g_{0}z-\dfrac{1}{2}\rho c z^{2} &=k\\ \end{align*}

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