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Question

The Chess Club at Asiniboyne High School consists of 6 seniors and 11 juniors. Presently, the club president and the club secretary are both seniors. (They must be different people.) If the students were selected randomly for these offices, what is the probability both would be seniors?

a. Show how to find the answer to this question using the General Multiplication Rule for probability.

b. Show how to find the answer using the Multiplication Principle of Counting and the definition of probability.

Solution

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A. Solve for the probability of selecting 22 seniors for the position of President and Secretary using the General Multiplication Rule for Probability given that there are 66 seniors and 1111 juniors in a chess club.

Let event AA and BB be choosing a senior.

P(A and B)=P(A)P(BA)=617516=30272=15136 or 0.1103 or 11.03%\begin{aligned} P( A \ and \ B)&=P(A) \cdot P(B|A)\\ &=\frac{6}{17} \cdot \frac{5}{16}\\ &=\frac{30}{272}\\ &=\frac{15}{136} \ or \ \approx 0.1103 \ or \ 11.03\% \end{aligned}

On event AA there is a total of 66 senior out of 1717 students so the probability of event AA will be 617\frac{6}{17}. Since a senior is already chosen on event AA, event BB given AA will be 516\frac{5}{16}. Therefore, the probability of choosing both seniors for the position is 15136 or 0.1103 or 11.03%\frac{15}{136} \ or \ \approx 0.1103 \ or \ 11.03\%.

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