## Related questions with answers

Question

The cross section for $0.01-\mathrm{MeV}$ neutrons to be captured by uranium 238 is $0.7$ barn. Two grams of ${ }^{238} \mathrm{U}$ is exposed to a flux of $3 \times 10^9$ neutrons per square meter (with energy $0.01 \mathrm{MeV}$ ). How many atoms of ${ }^{239} \mathrm{U}$ will be produced?

Solution

VerifiedAnswered 2 years ago

Answered 2 years ago

Step 1

1 of 5The reaction cross section $\sigma$ of a nucleus quantifies the effective target area for a flux of projectile $n_\text{inc}$. Our goal is to determine how many $^{239}\text{U}$ atoms can be produced from a $2\text{ g}$ of $^{238}\text U$ given the following:

$\begin{align*} \sigma&=0.7 \text{ barn}\\ n_\text{inc}&=3\times10^9\text{ neutrons/m}^2 \end{align*}$

## Create a free account to view solutions

By signing up, you accept Quizlet's Terms of Service and Privacy Policy

## Create a free account to view solutions

By signing up, you accept Quizlet's Terms of Service and Privacy Policy

## Recommended textbook solutions

#### Physics for Scientists and Engineers: A Strategic Approach with Modern Physics

4th Edition•ISBN: 9780133942651 (8 more)Randall D. Knight3,508 solutions

#### Modern Physics for Scientists and Engineers

2nd Edition•ISBN: 9780138057152 (3 more)Chris D. Zafiratos, John R. Taylor, Michael A. Dubson860 solutions

#### Mathematical Methods in the Physical Sciences

3rd Edition•ISBN: 9780471198260 (1 more)Mary L. Boas3,355 solutions

#### Fundamentals of Physics

10th Edition•ISBN: 9781118230718 (3 more)David Halliday, Jearl Walker, Robert Resnick8,971 solutions

## More related questions

1/4

1/7