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# The depth of water behind the Hoover Dam is $220 \mathrm{~m}$. Show that the water pressure at the base of this dam is $2200 \mathrm{kPa}$

Solution

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$\textbf{Given}$

$h = 220 \text{ m}$

$p = 2200 \text{ kPa}$

$\textbf{Approach}$

The water pressure can be calculated using the following equation:

$p = \rho \cdot g \cdot h$

$\textbf{Solution}$

Inserting numerical values into the equation we get that the pressure is:

$p = 1000$ $\dfrac{\text{kg}}{\text{m}^3} \cdot 10$ $\dfrac{\text{m}}{ \text{s}^2} \cdot 220 \text{ m} = 2200000 \text{ Pa}$

$\boxed {p = 2200 \text{ kPa}}$

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