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Question

The dial of a standard clock has a 10 -centimeter radius. One end of an elastic string is attached to the rim at 12 and the other to the tip of the 10-centimeter minute hand. At what rate is the string stretching at 12:15 (assuming that the clock is not slowed down by this stretching)?

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Answered 1 year ago
Answered 1 year ago
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In order to solve this task remind yourself that the minute hand makes one revolution, so it makes 6060 revolutions per hour. Now, it is clear that minute hand makes an angle of α=πt30\alpha=\frac{\pi t}{30} radians. Also, to solve this task remind yourself about the cosine law.

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