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Question

The difference between the heights of energy grade line (EGL) and hydraulic grade line (HGL) is equal to (a) z (b) $P/ ho g$ (c) $V^2/2g$ (d) $z + P/ ho g$ (e) $z + V^2/2g$

Solution

VerifiedAnswered 2 years ago

Answered 2 years ago

Step 1

1 of 2Height of energy grade line is, from Eq.$(5-48)$: $h_{EGL}=\frac{p}{\rho g}+\frac{V^2}{2g}+z$

Height of hydraulic grade line is, from Eq.$(5-48)$: $h_{HGL}=\frac{p}{\rho g}+z$.

Difference between these lines is:

$h_L=h_{EGL}-h_{HGL}=\frac{p}{\rho g}+\frac{V^2}{2g}+z-\frac{p}{\rho g}-z=\boxed{\frac{V^2}{2g}}$

Answer is c) $\frac{V^2}{2g}$

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