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The difference between the heights of energy grade line (EGL) and hydraulic grade line (HGL) is equal to (a) z (b) P/hogP/ ho g (c) V2/2gV^2/2g (d) z+P/hogz + P/ ho g (e) z+V2/2gz + V^2/2g

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Height of energy grade line is, from Eq.(548)(5-48): hEGL=pρg+V22g+zh_{EGL}=\frac{p}{\rho g}+\frac{V^2}{2g}+z

Height of hydraulic grade line is, from Eq.(548)(5-48): hHGL=pρg+zh_{HGL}=\frac{p}{\rho g}+z.

Difference between these lines is:

hL=hEGLhHGL=pρg+V22g+zpρgz=V22gh_L=h_{EGL}-h_{HGL}=\frac{p}{\rho g}+\frac{V^2}{2g}+z-\frac{p}{\rho g}-z=\boxed{\frac{V^2}{2g}}

Answer is c) V22g\frac{V^2}{2g}

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