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Question

The disk rotates in the horizontal plane with constant angular velocity Ω=12rad/s\Omega=12 \mathrm{rad} / \mathrm{s}. The mass m=2 kgm=2 \mathrm{~kg} slides in a smooth slot in the disk and is attached to a spring with constant k=860 N/mk=860 \mathrm{~N} / \mathrm{m}. The radial position of the mass when the spring is unstretched is r=0.2 mr=0.2 \mathrm{~m}. At t=0t=0, the mass is in the position r=0.4 mr=0.4 \mathrm{~m} and dr/dt=0d r / d t=0. Determine the position rr as a function of time.

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Given: Angular velocity: 12 rad/s12\ \text{rad/s} Mass of the slider: 2 kg2\ \text{kg} Spring constant: 860 N/m860\ \text{N/m} Position of the mass when spring is unstretched: 0.20 m0.20\ \text{m} Position at time, t=0 and dr/dt=0\text{dr}/\text{dt}=0: 0.40 m0.40\ \text{m}

We are required: To determine the position as a function of time.

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