## Related questions with answers

The Earth is surrounded by an electric field, pointing inward at every point, of magnitude $E \approx 150 \mathrm{~N} / \mathrm{C}$ near the surface. (b) How many excess electrons per square meter on the Earth's surface does this correspond to?

Solution

VerifiedIn part (a), we determined the total charge of the Earth. The total number of electrons can be obtained by dividing the total charge of the Earth by the charge of one electron which is equal to $q = -e = -1.6 \times 10 ^ {- 19} \, \mathrm {C}$. For the charge of the Earth we will use the value obtained in part (a), $Q = -6.79 \times 10 ^ {5} \, \mathrm {C}$.

$\begin{align*} N&=\dfrac{Q}{e}\\ &=\dfrac{-6.79 \times 10 ^ {5} \, \mathrm {C}}{ -1.6 \times 10 ^ {- 19} \, \mathrm {C}} \end{align*}$

$\begin{align*} \rightarrow N=4.2\times 10^{24} \,\,\,\text{electrons} \end{align*}$

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