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The electrons in the beam of a television tube have a kinetic energy of 12.0keV12.0 \mathrm{keV}. The tube is oriented so that the electrons move horizontally from magnetic south to magnetic north. The vertical component of the Earth's magnetic field points down and has a magnitude of 55.0μT55.0 \mu \mathrm{T}. (a) In what direction will the beam deflect? (b) What is the acceleration of a given electron due to the magnetic field? (c) How far will the beam deflect in moving 20.0 cm20.0 \mathrm{~cm} through the television tube?

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Part a\text{\underline{Part a}}.

Applying the right hand rule, we have the electrons moving due north, and the field pointing downwards. The right hand rule gives that a test charge would experience a force pointing due west. However, the electron has a negative charge, therefore the force it will experience will point eastwards. Thus, the beam will deflect due east.

Par b\text{\underline{Par b}}.

From Newton's second law, the acceleration experienced by the particle of mass mm when a force FF acts upon it will be

a=Fm.a=\frac{F}{m}.

The force in this case will be given by

F=qvB,F=qvB,

where BB is the known magnetic field, perpendicular to the velocity. Combining, we have

a=qvBm.a=\frac{qvB}{m}.

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