## Related questions with answers

The electrons in the beam of a television tube have a kinetic energy of $12.0 \mathrm{keV}$. The tube is oriented so that the electrons move horizontally from magnetic south to magnetic north. The vertical component of the Earth's magnetic field points down and has a magnitude of $55.0 \mu \mathrm{T}$. (a) In what direction will the beam deflect? (b) What is the acceleration of a given electron due to the magnetic field? (c) How far will the beam deflect in moving $20.0 \mathrm{~cm}$ through the television tube?

Solution

Verified$\text{\underline{Part a}}$.

Applying the right hand rule, we have the electrons moving due north, and the field pointing downwards. The right hand rule gives that a test charge would experience a force pointing due west. However, the electron has a negative charge, therefore the force it will experience will point eastwards. Thus, the beam will deflect due east.

$\text{\underline{Par b}}$.

From Newton's second law, the acceleration experienced by the particle of mass $m$ when a force $F$ acts upon it will be

$a=\frac{F}{m}.$

The force in this case will be given by

$F=qvB,$

where $B$ is the known magnetic field, perpendicular to the velocity. Combining, we have

$a=\frac{qvB}{m}.$

## Create a free account to view solutions

## Create a free account to view solutions

## Recommended textbook solutions

#### Physics for Scientists and Engineers: A Strategic Approach with Modern Physics

4th Edition•ISBN: 9780133942651 (8 more)Randall D. Knight#### Mathematical Methods in the Physical Sciences

3rd Edition•ISBN: 9780471198260 (1 more)Mary L. Boas#### Fundamentals of Physics

10th Edition•ISBN: 9781118230718 (3 more)David Halliday, Jearl Walker, Robert Resnick## More related questions

1/4

1/7