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# The equilibrium constant $\left(K_{\mathrm{c}}\right)$ for the reaction$2 \mathrm{HCl}(g) \rightleftharpoons \mathrm{H}_2(g)+\mathrm{Cl}_2(g)$is $4.17 \times 10^{-34}$ at $25^{\circ} \mathrm{C}$. What is the equilibrium constant for the reaction$\mathrm{H}_2(g)+\mathrm{Cl}_2(g) \rightleftharpoons 2 \mathrm{HCl}(g)$at the same temperature?

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The equilibrium constant $K_c$ for the reaction:

$\mathrm{2HCl_{(g)} \rightleftarrows H_{2(g)} + Cl_{2(g)}}$

is $4.17\cdot 10^{-34}$ at 25 degrees Celsius. We need to calculate the equilibrium constant for the reaction:

$\mathrm{H_{2(g)} + Cl_{2(g)} \rightleftarrows 2HCl_{(g)}}$

at the same temperature

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