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Question

The equilibrium constant (Kc)\left(K_{\mathrm{c}}\right) for the reaction

2HCl(g)H2(g)+Cl2(g)2 \mathrm{HCl}(g) \rightleftharpoons \mathrm{H}_2(g)+\mathrm{Cl}_2(g)

is 4.17×10344.17 \times 10^{-34} at 25C25^{\circ} \mathrm{C}. What is the equilibrium constant for the reaction

H2(g)+Cl2(g)2HCl(g)\mathrm{H}_2(g)+\mathrm{Cl}_2(g) \rightleftharpoons 2 \mathrm{HCl}(g)

at the same temperature?

Solution

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The equilibrium constant KcK_c for the reaction:

2HCl(g)H2(g)+Cl2(g)\mathrm{2HCl_{(g)} \rightleftarrows H_{2(g)} + Cl_{2(g)}}

is 4.1710344.17\cdot 10^{-34} at 25 degrees Celsius. We need to calculate the equilibrium constant for the reaction:

H2(g)+Cl2(g)2HCl(g)\mathrm{H_{2(g)} + Cl_{2(g)} \rightleftarrows 2HCl_{(g)}}

at the same temperature

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