Related questions with answers

The eyes of amphibians such as frogs have a much flatter cornea but a more strongly curved (almost spherical) lens than do the eyes of air-dwelling mammals. In mammalian eyes, the shape (and therefore the focal length) of the lens changes to enable the eye to focus at different distances. In amphibian eyes, the shape of the lens doesn’t change. Amphibians focus on objects at different distances by using specialized muscles to move the lens closer to or farther from the retina, like the focusing mechanism of a camera. In air, most frogs are nearsighted; correcting the distance vision of a typical frog in air would require contact lenses with a power of about –6.0 D. To determine whether a frog can judge distance by means of the amount its lens must move to focus on an object, researchers covered one eye with an opaque material. An insect was placed in front of the frog, and the distance that the frog snapped its tongue out to catch the insect was measured with high-speed video. The experiment was repeated with a contact lens over the eye to determine whether the frog could correctly judge the distance under these conditions. If such an experiment is performed twice, once with a lens of power –9 D and once with a lens of power –15 D, in which case does the frog have to focus at a shorter distance, and why? (a) With the –9-D lens; because the lenses are diverging, the lens with the longer focal length creates an image that is closer to the frog. (b) With the –15-D lens; because the lenses are diverging, the lens with the shorter focal length creates an image that is closer to the frog. (c) With the –9-D lens; because the lenses are converging, the lens with the longer focal length creates a larger real image. (d) With the –15-D lens; because the lenses are converging, the lens with the shorter focal length creates a larger real image.

Match the structure of the eye in Column A with its corresponding function or description in Column B.

Column AColumn B _______ corneaa. gland in which tears are formedb. hole in the eye that lets light inc. receptors for night vision or dim lightd. thick jellylike fluid of the eyee. tough, white outer layer of the eyef. receptors for red, blue, and green color visiong. structure on which ciliary muscles pull to help the eye focush. dark pigmented middle layer of the eye that prevents the scattering of incoming lighti. transparent part of the sclera, the window of the eyej. colored part of the anterior of the eyek. thin, watery fluid of the eye\begin{aligned} \text{Column A}\qquad \qquad \qquad &\text{Column B}\\ \text{ \_\_\_\_\_\_\_ cornea}\qquad \qquad \qquad\quad & \text{a. gland in which tears are formed}\\ &\text{b. hole in the eye that lets light in}\\ &\text{c. receptors for night vision or dim light}\\ &\text{d. thick jellylike fluid of the eye}\\ &\text{e. tough, white outer layer of the eye}\\ &\text{f. receptors for red, blue, and green color vision}\\ &\text{g. structure on which ciliary muscles pull to help the eye focus}\\ &\text{h. dark pigmented middle layer of the eye that prevents the scattering of incoming light}\\ &\text{i. transparent part of the sclera, the window of the eye}\\ &\text{j. colored part of the anterior of the eye}\\ &\text{k. thin, watery fluid of the eye}\\ \end{aligned}

Question

The eyes of amphibians such as frogs have a much flatter cornea but a more strongly curved (almost spherical) lens than do the eyes of air-dwelling mammals. In mammalian eyes, the shape (and therefore the focal length) of the lens changes to enable the eye to focus at different distances. In amphibian eyes, the shape of the lens doesn’t change. Amphibians focus on objects at different distances by using specialized muscles to move the lens closer to or farther from the retina, like the focusing mechanism of a camera. In air, most frogs are nearsighted; correcting the distance vision of a typical frog in air would require contact lenses with a power of about –6.0 D. What is the farthest distance at which a typical “nearsighted” frog can see clearly in air? (a) 12 m; (b) 6.0 m; (c) 80 cm; (d) 17 cm.

Solution

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The power of the lens is given by

P=1s+1sP = \dfrac{1}{s} + \dfrac{1}{s'}

Now, we solve this equation for ss and plug the values for P=6 D=6 m1P = 6 \mathrm{~D} = 6 \mathrm{~m^{-1}} and s=s' = \infty

P=1s+1s1s=P1s1s=6 m11\begin{gather*} P = \dfrac{1}{s} + \dfrac{1}{s'}\\ \dfrac{1}{s} = P - \dfrac{1}{s'}\\ \dfrac{1}{s} = 6 \mathrm{~m^{-1}} - \dfrac{1}{\infty}\\ \end{gather*}

Hence, s=0.17s = 0.17 m = 17 cm. The correct answer is  (d) 17 cm\textbf{ (d) 17 cm}

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