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Question

The flow lines (or streamlines) of a vector field are the paths followed by a particle whose velocity field is the given vector field. Thus the vectors in a vector field are tangent to the flow lines. If parametric equations of a flow line are x=x(t),y=y(t)x = x(t), y = y(t) explain why these functions satisfy the differential equations dx/dt=xdx/dt = x and dy/dt=ydy/dt = -y. Then solve the differential equations to find an equation of the flow line that passes through the point (1, 1).

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Answered 5 months ago
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At any point dxdt\dfrac{dx}{dt} is the xx component of the velocity.

At any point dydt\dfrac{dy}{dt} is the yy component of the velocity.

Here it is given that Velocity at the point (x,y(x, y) is F(x,y)=x i y j \textbf{F}(x, y) = x\textbf{ i }-y\textbf{ j }

Note that, the xx component of the velocity is xx and

the yy-component of the velocity is y-y

Therefore, we can write

dxdt=x(1)\dfrac{dx}{dt} = x \rightarrow \textbf{(1)}

dydt=y(2)\dfrac{dy}{dt} = -y \rightarrow \textbf{(2)}

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