## Related questions with answers

The flywheel of an old steam engine is a solid homogeneous metal disk of mass $M=120 \mathrm{~kg}$ and radius $R=80.0 \mathrm{~cm}$. The engine rotates the wheel at 500 . rpm. In an emergency, to bring the engine to a stop, the flywheel is disengaged from the engine and a brake pad is applied at the edge to provide a radially inward force $F=100$. N. If the coefficient of kinetic friction between the pad and the flywheel is $\mu_{\mathrm{k}}=0.200$, how many revolutions does the flywheel make before coming to rest? How long does it take for the flywheel to come to rest? Calculate the work done by the torque during this time.

Solution

Verified**The known values:**

Mass of the metal disc $\rightarrow M=120\text{ kg}$ Radius of the metal disc $\rightarrow R=0.8\text{ m}$ Rate at which wheel rotates $\rightarrow \omega =500\text{ rpm}$ Applied force $\rightarrow F=100\text{ N}$ Coefficient of kinetic friction $\rightarrow \mu_{k}=0.2$

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