Try the fastest way to create flashcards
Question

The following problem is based on material learned earlier in the course. The purpose of these problems is to keep the material fresh in your mind so that you are better prepared for the final exam.

Given f(x)=x+4f(x)=x+4 and g(x)=x23xg(x)=x^2-3 x, find g(f(3))g(f(-3)).

Solution

Verified
Answered 1 year ago
Answered 1 year ago
Step 1
1 of 4

Let us first evaluate f(3)f(-3) by substituting 3-3 to f(x)f(x):

f(x)=x+4f(3)=(3)+4=1 .\begin{aligned} f(x)&=x+4\\ f(-3)&=(-3)+4\\ &=1\text{ }. \end{aligned}

Create a free account to view solutions

Create a free account to view solutions

Recommended textbook solutions

Precalculus 2nd Edition by Carter, Cuevas, Day, Malloy

Precalculus

2nd EditionISBN: 9780076602186Carter, Cuevas, Day, Malloy
8,886 solutions
Nelson Functions 11 1st Edition by Chris Kirkpatrick, Marian Small

Nelson Functions 11

1st EditionISBN: 9780176332037Chris Kirkpatrick, Marian Small
1,275 solutions
Precalculus: Concepts Through Functions: A Unit Circle Approach to Trigonometry 3rd Edition by Michael Sullivan, Michael Sullivan III

Precalculus: Concepts Through Functions: A Unit Circle Approach to Trigonometry

3rd EditionISBN: 9780321931047Michael Sullivan, Michael Sullivan III
8,933 solutions
Precalculus with Limits 3rd Edition by Larson

Precalculus with Limits

3rd EditionISBN: 9781133962885 (1 more)Larson
11,135 solutions

More related questions

1/4

1/7