The following table gives the top ten countries in the world whose populations have the highest concentration of type $\mathrm{O}^{+}$ blood:

Country Saudi Arabia Iceland Ireland Taiwan Australia

Population (%) $48.0$ $47.6$ $47.0$ $43.9$ $40.0$

Country Hong Kong Italy Netherlands Canada South Africa

Population (%) $40.0$ $39.5$ $39.0$ $39.0$ $38.0$

Find the mean (average), median, and mode of these concentrations of type $\mathrm{O}^{+}$ blood in these ten countries.

Country	Saudi Arabia	Iceland	Ireland	Taiwan	Australia
Population (%)	$48.0$	$47.6$	$47.0$	$43.9$	$40.0$

Country	Hong Kong	Italy	Netherlands	Canada	South Africa
Population (%)	$40.0$	$39.5$	$39.0$	$39.0$	$38.0$

Solution

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Step 1

1 of 2

The mean is given by:

\begin{equation} \begin{aligned} \overline{x}& = \dfrac{x_1 + x_2 + ... + x_n}{n}\\ &= \quad \dfrac{48.0+ 47.6+ 47.0 + 43.9+ 40.0+ 40.0+ 39.5 + 39.0 + 39.0 + 38.0}{10} \\ & = \dfrac{422}{10}\\ & = 42.2 \end{aligned} \end{equation}

The mean of these concentrations of type $\text{O}^+$ blood in these ten countries is $42.2 \%$ .

To find the median, we arrange the values in increasing order.

38.0,\quad 39.0,\quad 39.0 ,\quad 39.5,\quad 40,\quad 40,\quad 43.9,\quad 47,\quad 47.6,\quad 48

We have $10$ terms, the median is the average of the $5th$ and $6th$ terms.:

\begin{equation} \begin{aligned} \text {Median}& = \dfrac{40+ 40}{2}\\ &= \dfrac{80}{2}\\ &= 40 \end{aligned} \end{equation}

The median of these concentrations of type $\text{O}^+$ blood in these ten countries is $40 \%$ .

Mode: $39$ and $40$ (because each number occurs two times)

The modes of these concentrations of type $\text{O}^+$ blood in these ten countries are $39\%$ and $40\%$ .

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